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102169553407 = 412491940327
BaseRepresentation
bin101111100100111000…
…1111010100111111111
3100202201101001002000121
41133021301322213333
53133220401202112
6114534104035411
710244566606045
oct1371161724777
9322641032017
10102169553407
113a36a05a749
1217974462b67
139833140a5c
144d33254395
1529ce940407
hex17c9c7a9ff

102169553407 has 4 divisors (see below), whose sum is σ = 104661493776. Its totient is φ = 99677613040.

The previous prime is 102169553401. The next prime is 102169553417. The reversal of 102169553407 is 704355961201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102169553407 - 23 = 102169553399 is a prime.

It is a super-3 number, since 3×1021695534073 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102169553401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1245970123 + ... + 1245970204.

It is an arithmetic number, because the mean of its divisors is an integer number (26165373444).

Almost surely, 2102169553407 is an apocalyptic number.

102169553407 is a deficient number, since it is larger than the sum of its proper divisors (2491940369).

102169553407 is an equidigital number, since it uses as much as digits as its factorization.

102169553407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2491940368.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 102169553407 in words is "one hundred two billion, one hundred sixty-nine million, five hundred fifty-three thousand, four hundred seven".

Divisors: 1 41 2491940327 102169553407