Base | Representation |
---|---|
bin | 11101101111101011100… |
… | …11010100011101001011 |
3 | 10121201001002212021211222 |
4 | 32313311303110131023 |
5 | 113221104431321303 |
6 | 2101303053512255 |
7 | 133560612120122 |
oct | 16676563243513 |
9 | 3551032767758 |
10 | 1022031120203 |
11 | 364493a17655 |
12 | 1460b01a268b |
13 | 754b96c5642 |
14 | 376763a8ab9 |
15 | 1b8ba990938 |
hex | edf5cd474b |
1022031120203 has 32 divisors (see below), whose sum is σ = 1166448771072. Its totient is φ = 889780953600.
The previous prime is 1022031120199. The next prime is 1022031120211. The reversal of 1022031120203 is 3020211302201.
It is a cyclic number.
It is not a de Polignac number, because 1022031120203 - 22 = 1022031120199 is a prime.
It is a super-2 number, since 2×10220311202032 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is not an unprimeable number, because it can be changed into a prime (1022031120223) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17582798 + ... + 17640828.
It is an arithmetic number, because the mean of its divisors is an integer number (36451524096).
Almost surely, 21022031120203 is an apocalyptic number.
1022031120203 is a deficient number, since it is larger than the sum of its proper divisors (144417650869).
1022031120203 is a wasteful number, since it uses less digits than its factorization.
1022031120203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59555.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1022031120203 its reverse (3020211302201), we get a palindrome (4042242422404).
The spelling of 1022031120203 in words is "one trillion, twenty-two billion, thirty-one million, one hundred twenty thousand, two hundred three".
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