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102213002002 = 251106501001
BaseRepresentation
bin101111100110001011…
…1101010001100010010
3100202211101210111021211
41133030113222030102
53133313012031002
6114542255210334
710245635116246
oct1371427521422
9322741714254
10102213002002
113a391636281
1217986b169aa
13983c144197
144d38d24426
1529d3673dd7
hex17cc5ea312

102213002002 has 4 divisors (see below), whose sum is σ = 153319503006. Its totient is φ = 51106501000.

The previous prime is 102213001999. The next prime is 102213002011. The reversal of 102213002002 is 200200312201.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200200312201 = 1711776488953.

It can be written as a sum of positive squares in only one way, i.e., 75020662201 + 27192339801 = 273899^2 + 164901^2 .

It is a super-3 number, since 3×1022130020023 (a number of 34 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25553250499 + ... + 25553250502.

Almost surely, 2102213002002 is an apocalyptic number.

102213002002 is a deficient number, since it is larger than the sum of its proper divisors (51106501004).

102213002002 is an equidigital number, since it uses as much as digits as its factorization.

102213002002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51106501003.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 102213002002 its reverse (200200312201), we get a palindrome (302413314203).

The spelling of 102213002002 in words is "one hundred two billion, two hundred thirteen million, two thousand, two".

Divisors: 1 2 51106501001 102213002002