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102233141251 = 199351296107
BaseRepresentation
bin101111100110110010…
…0011111000000000011
3100202212210200200010221
41133031210133000003
53133333141010001
6114544255003511
710246301235253
oct1371544370003
9322783620127
10102233141251
113a3a1a4118a
1217991809597
139843375ab7
144d3b887963
1529d53011a1
hex17cd91f003

102233141251 has 4 divisors (see below), whose sum is σ = 102284439352. Its totient is φ = 102181843152.

The previous prime is 102233141239. The next prime is 102233141261. The reversal of 102233141251 is 152141332201.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 152141332201 = 1371110520673.

It is a cyclic number.

It is not a de Polignac number, because 102233141251 - 233 = 93643206659 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102233141201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25646061 + ... + 25650046.

It is an arithmetic number, because the mean of its divisors is an integer number (25571109838).

Almost surely, 2102233141251 is an apocalyptic number.

102233141251 is a deficient number, since it is larger than the sum of its proper divisors (51298101).

102233141251 is an equidigital number, since it uses as much as digits as its factorization.

102233141251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51298100.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 102233141251 its reverse (152141332201), we get a palindrome (254374473452).

The spelling of 102233141251 in words is "one hundred two billion, two hundred thirty-three million, one hundred forty-one thousand, two hundred fifty-one".

Divisors: 1 1993 51296107 102233141251