| Base | Representation |
|---|---|
| bin | 1001010011100001111011… |
| … | …1111010100001000101100 |
| 3 | 1100020002100011220001202000 |
| 4 | 2110320132333110020230 |
| 5 | 2320111324243404400 |
| 6 | 33432041150132300 |
| 7 | 2104113663135015 |
| oct | 224703677241054 |
| 9 | 40202304801660 |
| 10 | 10231132013100 |
| 11 | 3294aa9329469 |
| 12 | 1192a414b1090 |
| 13 | 592a3a21b80b |
| 14 | 275291b2c00c |
| 15 | 12b20659c600 |
| hex | 94e1efd422c |
10231132013100 has 288 divisors, whose sum is σ = 33083996447040. Its totient is φ = 2712328519680.
The previous prime is 10231132013093. The next prime is 10231132013101. The reversal of 10231132013100 is 131023113201.
10231132013100 is a `hidden beast` number, since 1 + 0 + 2 + 31 + 1 + 320 + 1 + 310 + 0 = 666.
10231132013100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×102311320131002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (10231132013101) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 882216502 + ... + 882228098.
Almost surely, 210231132013100 is an apocalyptic number.
10231132013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10231132013100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16541998223520).
10231132013100 is an abundant number, since it is smaller than the sum of its proper divisors (22852864433940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10231132013100 is a wasteful number, since it uses less digits than its factorization.
10231132013100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13506 (or 13493 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 10231132013100 its reverse (131023113201), we get a palindrome (10362155126301).
The spelling of 10231132013100 in words is "ten trillion, two hundred thirty-one billion, one hundred thirty-two million, thirteen thousand, one hundred".
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