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10234113 = 313126041
BaseRepresentation
bin100111000010…
…100100000001
3201020221120020
4213002210001
510104442423
61003204053
7152663031
oct47024401
921227506
1010234113
11586004a
123516629
1321742b6
1415058c1
15d724e3
hex9c2901

10234113 has 8 divisors (see below), whose sum is σ = 13750176. Its totient is φ = 6770400.

The previous prime is 10234111. The next prime is 10234117. The reversal of 10234113 is 31143201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10234113 - 21 = 10234111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10234092 and 10234101.

It is not an unprimeable number, because it can be changed into a prime (10234111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12628 + ... + 13413.

It is an arithmetic number, because the mean of its divisors is an integer number (1718772).

Almost surely, 210234113 is an apocalyptic number.

It is an amenable number.

10234113 is a deficient number, since it is larger than the sum of its proper divisors (3516063).

10234113 is a wasteful number, since it uses less digits than its factorization.

10234113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26175.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 10234113 is about 3199.0800240069. The cubic root of 10234113 is about 217.1117873491. Note that the first 3 decimals are identical.

Adding to 10234113 its reverse (31143201), we get a palindrome (41377314).

The spelling of 10234113 in words is "ten million, two hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 131 393 26041 78123 3411371 10234113