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102363135051 = 338261891797
BaseRepresentation
bin101111101010101010…
…0010111110001001011
3100210012212022001010010
41133111110113301023
53134114430310201
6115005221123003
710252440202032
oct1372524276113
9323185261103
10102363135051
113a459359481
1217a09259463
13986428b7c8
144d50c45719
1529e192cbd6
hex17d5517c4b

102363135051 has 8 divisors (see below), whose sum is σ = 136487900304. Its totient is φ = 68240229920.

The previous prime is 102363135031. The next prime is 102363135101. The reversal of 102363135051 is 150531363201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 102363135051 - 29 = 102363134539 is a prime.

It is a super-2 number, since 2×1023631350512 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (102363135031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 331116 + ... + 560681.

It is an arithmetic number, because the mean of its divisors is an integer number (17060987538).

Almost surely, 2102363135051 is an apocalyptic number.

102363135051 is a deficient number, since it is larger than the sum of its proper divisors (34124765253).

102363135051 is an equidigital number, since it uses as much as digits as its factorization.

102363135051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 930061.

The product of its (nonzero) digits is 8100, while the sum is 30.

Adding to 102363135051 its reverse (150531363201), we get a palindrome (252894498252).

The spelling of 102363135051 in words is "one hundred two billion, three hundred sixty-three million, one hundred thirty-five thousand, fifty-one".

Divisors: 1 3 38261 114783 891797 2675391 34121045017 102363135051