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10241311413 = 33413770471
BaseRepresentation
bin10011000100110111…
…00000001010110101
3222102201211112011010
421202123200022311
5131433233431123
64412122502433
7511534465524
oct114233401265
928381745133
1010241311413
114385a53933
121b99964a19
13c729aa1a8
146d221a4bb
153ee177993
hex2626e02b5

10241311413 has 4 divisors (see below), whose sum is σ = 13655081888. Its totient is φ = 6827540940.

The previous prime is 10241311397. The next prime is 10241311439. The reversal of 10241311413 is 31411314201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10241311413 - 24 = 10241311397 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10241311413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10241311463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1706885233 + ... + 1706885238.

It is an arithmetic number, because the mean of its divisors is an integer number (3413770472).

Almost surely, 210241311413 is an apocalyptic number.

It is an amenable number.

10241311413 is a deficient number, since it is larger than the sum of its proper divisors (3413770475).

10241311413 is an equidigital number, since it uses as much as digits as its factorization.

10241311413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3413770474.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 10241311413 its reverse (31411314201), we get a palindrome (41652625614).

The spelling of 10241311413 in words is "ten billion, two hundred forty-one million, three hundred eleven thousand, four hundred thirteen".

Divisors: 1 3 3413770471 10241311413