Base | Representation |
---|---|
bin | 1001010100001011100110… |
… | …0000011001101011110001 |
3 | 1100021011012111100201122120 |
4 | 2111002321200121223301 |
5 | 2320302224430444213 |
6 | 33441130525424453 |
7 | 2104661045123550 |
oct | 225027140315361 |
9 | 40234174321576 |
10 | 10242314312433 |
11 | 329981745a465 |
12 | 119504240b129 |
13 | 593accb43798 |
14 | 275a32cd3d97 |
15 | 12b65d14b423 |
hex | 950b9819af1 |
10242314312433 has 32 divisors (see below), whose sum is σ = 15657609090816. Its totient is φ = 5833928921088.
The previous prime is 10242314312413. The next prime is 10242314312513. The reversal of 10242314312433 is 33421341324201.
It is not a de Polignac number, because 10242314312433 - 221 = 10242312215281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10242314312394 and 10242314312403.
It is not an unprimeable number, because it can be changed into a prime (10242314312413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7502041 + ... + 8761577.
It is an arithmetic number, because the mean of its divisors is an integer number (489300284088).
Almost surely, 210242314312433 is an apocalyptic number.
It is an amenable number.
10242314312433 is a deficient number, since it is larger than the sum of its proper divisors (5415294778383).
10242314312433 is a wasteful number, since it uses less digits than its factorization.
10242314312433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1260793.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 10242314312433 its reverse (33421341324201), we get a palindrome (43663655636634).
The spelling of 10242314312433 in words is "ten trillion, two hundred forty-two billion, three hundred fourteen million, three hundred twelve thousand, four hundred thirty-three".
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