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102553465301 = 714650495043
BaseRepresentation
bin101111110000010101…
…0011011000111010101
3100210201010102211010122
41133200222123013111
53140012141342201
6115040140401325
710260241033520
oct1374052330725
9323633384118
10102553465301
113a546837401
1217a60b46245
13989483b661
144d6c22bbb7
152a034c6e1b
hex17e0a9b1d5

102553465301 has 4 divisors (see below), whose sum is σ = 117203960352. Its totient is φ = 87902970252.

The previous prime is 102553465247. The next prime is 102553465309. The reversal of 102553465301 is 103564355201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102553465301 is a prime.

It is a super-2 number, since 2×1025534653012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102553465309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7325247515 + ... + 7325247528.

It is an arithmetic number, because the mean of its divisors is an integer number (29300990088).

Almost surely, 2102553465301 is an apocalyptic number.

It is an amenable number.

102553465301 is a deficient number, since it is larger than the sum of its proper divisors (14650495051).

102553465301 is an equidigital number, since it uses as much as digits as its factorization.

102553465301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14650495050.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 102553465301 in words is "one hundred two billion, five hundred fifty-three million, four hundred sixty-five thousand, three hundred one".

Divisors: 1 7 14650495043 102553465301