Base | Representation |
---|---|
bin | 101111110011100010… |
… | …1100011101001000101 |
3 | 100210222122020102011111 |
4 | 1133213011203221011 |
5 | 3140222234211123 |
6 | 115054550405021 |
7 | 10263020103553 |
oct | 1374705435105 |
9 | 323878212144 |
10 | 102661241413 |
11 | 3a5a165a175 |
12 | 17a91060771 |
13 | 98b0c756c3 |
14 | 4d7c684bd3 |
15 | 2a0cbb590d |
hex | 17e7163a45 |
102661241413 has 4 divisors (see below), whose sum is σ = 102726590688. Its totient is φ = 102595892140.
The previous prime is 102661241411. The next prime is 102661241437. The reversal of 102661241413 is 314142166201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 102661241413 - 21 = 102661241411 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102661241411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32672281 + ... + 32675422.
It is an arithmetic number, because the mean of its divisors is an integer number (25681647672).
Almost surely, 2102661241413 is an apocalyptic number.
It is an amenable number.
102661241413 is a deficient number, since it is larger than the sum of its proper divisors (65349275).
102661241413 is an equidigital number, since it uses as much as digits as its factorization.
102661241413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65349274.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 102661241413 in words is "one hundred two billion, six hundred sixty-one million, two hundred forty-one thousand, four hundred thirteen".
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