Base | Representation |
---|---|
bin | 101111111101011000… |
… | …1111010000110100101 |
3 | 100211211122221010202120 |
4 | 1133322301322012211 |
5 | 3141411324303403 |
6 | 115151432100153 |
7 | 10304141311002 |
oct | 1377261720645 |
9 | 324748833676 |
10 | 102991634853 |
11 | 3a7511026a8 |
12 | 17b63834659 |
13 | 9934555593 |
14 | 4db04ca8a9 |
15 | 2a2bbc9e53 |
hex | 17fac7a1a5 |
102991634853 has 4 divisors (see below), whose sum is σ = 137322179808. Its totient is φ = 68661089900.
The previous prime is 102991634827. The next prime is 102991634873. The reversal of 102991634853 is 358436199201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 102991634853 - 218 = 102991372709 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102991634796 and 102991634805.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102991634873) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17165272473 + ... + 17165272478.
It is an arithmetic number, because the mean of its divisors is an integer number (34330544952).
Almost surely, 2102991634853 is an apocalyptic number.
It is an amenable number.
102991634853 is a deficient number, since it is larger than the sum of its proper divisors (34330544955).
102991634853 is an equidigital number, since it uses as much as digits as its factorization.
102991634853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34330544954.
The product of its (nonzero) digits is 1399680, while the sum is 51.
The spelling of 102991634853 in words is "one hundred two billion, nine hundred ninety-one million, six hundred thirty-four thousand, eight hundred fifty-three".
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