103010113111 has 4 divisors (see below), whose sum is σ = 103011135192. Its totient is φ = 103009091032.

The previous prime is 103010113093. The next prime is 103010113117. The reversal of 103010113111 is 111311010301.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 103010113111 - 2⁷ = 103010112983 is a prime.

It is a super-2 number, since 2×103010113111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103010113091 and 103010113100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103010113117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341005 + ... + 567718.

It is an arithmetic number, because the mean of its divisors is an integer number (25752783798).

Almost surely, 2^103010113111 is an apocalyptic number.

103010113111 is a deficient number, since it is larger than the sum of its proper divisors (1022081).

103010113111 is an equidigital number, since it uses as much as digits as its factorization.

103010113111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1022080.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 103010113111 its reverse (111311010301), we get a palindrome (214321123412).

The spelling of 103010113111 in words is "one hundred three billion, ten million, one hundred thirteen thousand, one hundred eleven".