Base | Representation |
---|---|
bin | 1001010111100110010100… |
… | …1111011100001000011101 |
3 | 1100110202202111111220022122 |
4 | 2111321211033130020131 |
5 | 2322233002202401023 |
6 | 33524121121152325 |
7 | 2112140062225061 |
oct | 225714517341035 |
9 | 40422674456278 |
10 | 10301030122013 |
11 | 3311707a58224 |
12 | 11a44aa18b6a5 |
13 | 5994c950c987 |
14 | 278802dbdaa1 |
15 | 12ce47c832c8 |
hex | 95e653dc21d |
10301030122013 has 4 divisors (see below), whose sum is σ = 10454776840320. Its totient is φ = 10147283403708.
The previous prime is 10301030122003. The next prime is 10301030122051. The reversal of 10301030122013 is 31022103010301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10301030122013 - 24 = 10301030121997 is a prime.
It is a super-2 number, since 2×103010301220132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10301030121982 and 10301030122000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10301030122003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76873359053 + ... + 76873359186.
It is an arithmetic number, because the mean of its divisors is an integer number (2613694210080).
Almost surely, 210301030122013 is an apocalyptic number.
It is an amenable number.
10301030122013 is a deficient number, since it is larger than the sum of its proper divisors (153746718307).
10301030122013 is an equidigital number, since it uses as much as digits as its factorization.
10301030122013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153746718306.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 10301030122013 its reverse (31022103010301), we get a palindrome (41323133132314).
The spelling of 10301030122013 in words is "ten trillion, three hundred one billion, thirty million, one hundred twenty-two thousand, thirteen".
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