103011123141103 has 4 divisors (see below), whose sum is σ = 105795207550360. Its totient is φ = 100227038731848.

The previous prime is 103011123141077. The next prime is 103011123141151. The reversal of 103011123141103 is 301141321110301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103011123141103 - 2⁵ = 103011123141071 is a prime.

It is a super-3 number, since 3×103011123141103³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103011123141803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1392042204573 + ... + 1392042204646.

It is an arithmetic number, because the mean of its divisors is an integer number (26448801887590).

Almost surely, 2^{103011123141103} is an apocalyptic number.

103011123141103 is a deficient number, since it is larger than the sum of its proper divisors (2784084409257).

103011123141103 is an equidigital number, since it uses as much as digits as its factorization.

103011123141103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2784084409256.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 103011123141103 its reverse (301141321110301), we get a palindrome (404152444251404).

The spelling of 103011123141103 in words is "one hundred three trillion, eleven billion, one hundred twenty-three million, one hundred forty-one thousand, one hundred three".