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103011312143 = 313322945553
BaseRepresentation
bin101111111101111110…
…0111110001000001111
3100211220000221211221002
41133323330332020033
53141431343442033
6115153413530515
710304500464125
oct1377374761017
9324800854832
10103011312143
113a761222523
1217b6a343a3b
139938654b4c
144db2d6d915
152a2d7b53e8
hex17fbf3e20f

103011312143 has 4 divisors (see below), whose sum is σ = 106334257728. Its totient is φ = 99688366560.

The previous prime is 103011312127. The next prime is 103011312161. The reversal of 103011312143 is 341213110301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 103011312143 - 24 = 103011312127 is a prime.

It is a super-2 number, since 2×1030113121432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103011312113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1661472746 + ... + 1661472807.

It is an arithmetic number, because the mean of its divisors is an integer number (26583564432).

Almost surely, 2103011312143 is an apocalyptic number.

103011312143 is a deficient number, since it is larger than the sum of its proper divisors (3322945585).

103011312143 is an equidigital number, since it uses as much as digits as its factorization.

103011312143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3322945584.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 103011312143 its reverse (341213110301), we get a palindrome (444224422444).

The spelling of 103011312143 in words is "one hundred three billion, eleven million, three hundred twelve thousand, one hundred forty-three".

Divisors: 1 31 3322945553 103011312143