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103013021114 = 251506510557
BaseRepresentation
bin101111111110000001…
…1011111010110111010
3100211220011011200012022
41133330003133112322
53141432313133424
6115153514314442
710304521142423
oct1377403372672
9324804150168
10103013021114
113a76218a4a3
1217b6aa28a22
139938b02983
144db329664a
152a2da0195e
hex17fc0df5ba

103013021114 has 4 divisors (see below), whose sum is σ = 154519531674. Its totient is φ = 51506510556.

The previous prime is 103013021113. The next prime is 103013021119. The reversal of 103013021114 is 411120310301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 94762387225 + 8250633889 = 307835^2 + 90833^2 .

It is a super-2 number, since 2×1030130211142 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103013021092 and 103013021101.

It is not an unprimeable number, because it can be changed into a prime (103013021113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25753255277 + ... + 25753255280.

Almost surely, 2103013021114 is an apocalyptic number.

103013021114 is a deficient number, since it is larger than the sum of its proper divisors (51506510560).

103013021114 is an equidigital number, since it uses as much as digits as its factorization.

103013021114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51506510559.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 103013021114 its reverse (411120310301), we get a palindrome (514133331415).

The spelling of 103013021114 in words is "one hundred three billion, thirteen million, twenty-one thousand, one hundred fourteen".

Divisors: 1 2 51506510557 103013021114