Base | Representation |
---|---|
bin | 11101111110111010110… |
… | …11010010010000000010 |
3 | 10122111011020211011220021 |
4 | 32333131123102100002 |
5 | 113334333244213442 |
6 | 2105134540404054 |
7 | 134300421242341 |
oct | 16773533222002 |
9 | 3574136734807 |
10 | 1030212101122 |
11 | 367a01967706 |
12 | 1477b3b4662a |
13 | 761c1593c59 |
14 | 37c10b03b58 |
15 | 1bbe8cd9e67 |
hex | efdd6d2402 |
1030212101122 has 8 divisors (see below), whose sum is σ = 1545382088316. Its totient is φ = 515084738352.
The previous prime is 1030212101069. The next prime is 1030212101141. The reversal of 1030212101122 is 2211012120301.
It can be written as a sum of positive squares in 2 ways, for example, as 1027082929401 + 3129171721 = 1013451^2 + 55939^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×10302121011222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1030212101096 and 1030212101105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10595613 + ... + 10692400.
Almost surely, 21030212101122 is an apocalyptic number.
1030212101122 is a deficient number, since it is larger than the sum of its proper divisors (515169987194).
1030212101122 is a wasteful number, since it uses less digits than its factorization.
1030212101122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21312212.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1030212101122 its reverse (2211012120301), we get a palindrome (3241224221423).
The spelling of 1030212101122 in words is "one trillion, thirty billion, two hundred twelve million, one hundred one thousand, one hundred twenty-two".
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