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103021300103 = 234479186961
BaseRepresentation
bin101111111110010001…
…1000100100110000111
3100211220201202021211112
41133330203010212013
53141441423100403
6115154411555235
710304651413421
oct1377443044607
9324821667745
10103021300103
113a766924637
1217b7175bb1b
13993a741097
144db440d811
152a2e5d99d8
hex17fc8c4987

103021300103 has 4 divisors (see below), whose sum is σ = 107500487088. Its totient is φ = 98542113120.

The previous prime is 103021300099. The next prime is 103021300133. The reversal of 103021300103 is 301003120301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103021300103 - 22 = 103021300099 is a prime.

It is a super-2 number, since 2×1030213001032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103021300133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2239593458 + ... + 2239593503.

It is an arithmetic number, because the mean of its divisors is an integer number (26875121772).

Almost surely, 2103021300103 is an apocalyptic number.

103021300103 is a deficient number, since it is larger than the sum of its proper divisors (4479186985).

103021300103 is an equidigital number, since it uses as much as digits as its factorization.

103021300103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4479186984.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 103021300103 its reverse (301003120301), we get a palindrome (404024420404).

The spelling of 103021300103 in words is "one hundred three billion, twenty-one million, three hundred thousand, one hundred three".

Divisors: 1 23 4479186961 103021300103