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1030214314411 = 4127249627893
BaseRepresentation
bin11101111110111011000…
…11101110100110101011
310122111011101222121221221
432333131203232212223
5113334334331030121
62105135100042511
7134300446121152
oct16773543564653
93574141877857
101030214314411
11367a03139577
121477b4833437
13761c1b8a4a9
1437c1111c599
151bbe90c5b41
hexefdd8ee9ab

1030214314411 has 4 divisors (see below), whose sum is σ = 1030463946432. Its totient is φ = 1029964682392.

The previous prime is 1030214314387. The next prime is 1030214314463. The reversal of 1030214314411 is 1144134120301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1030214314411 - 223 = 1030205925803 is a prime.

It is a super-2 number, since 2×10302143144112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1030214314111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124809820 + ... + 124818073.

It is an arithmetic number, because the mean of its divisors is an integer number (257615986608).

Almost surely, 21030214314411 is an apocalyptic number.

1030214314411 is a deficient number, since it is larger than the sum of its proper divisors (249632021).

1030214314411 is an equidigital number, since it uses as much as digits as its factorization.

1030214314411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249632020.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1030214314411 its reverse (1144134120301), we get a palindrome (2174348434712).

The spelling of 1030214314411 in words is "one trillion, thirty billion, two hundred fourteen million, three hundred fourteen thousand, four hundred eleven".

Divisors: 1 4127 249627893 1030214314411