Base | Representation |
---|---|
bin | 11101111110111100111… |
… | …11100100100111001010 |
3 | 10122111012111111122110021 |
4 | 32333132133210213022 |
5 | 113334402340031442 |
6 | 2105140420211054 |
7 | 134301026350006 |
oct | 16773637444712 |
9 | 3574174448407 |
10 | 1030230002122 |
11 | 367a10a83a22 |
12 | 1477b9b39a8a |
13 | 761c51c0b69 |
14 | 37c13243706 |
15 | 1bbea673e67 |
hex | efde7e49ca |
1030230002122 has 4 divisors (see below), whose sum is σ = 1545345003186. Its totient is φ = 515115001060.
The previous prime is 1030230002083. The next prime is 1030230002141. The reversal of 1030230002122 is 2212000320301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 637089716041 + 393140286081 = 798179^2 + 627009^2 .
It is a super-2 number, since 2×10302300021222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1030230002096 and 1030230002105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257557500529 + ... + 257557500532.
Almost surely, 21030230002122 is an apocalyptic number.
1030230002122 is a deficient number, since it is larger than the sum of its proper divisors (515115001064).
1030230002122 is an equidigital number, since it uses as much as digits as its factorization.
1030230002122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515115001063.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 1030230002122 its reverse (2212000320301), we get a palindrome (3242230322423).
The spelling of 1030230002122 in words is "one trillion, thirty billion, two hundred thirty million, two thousand, one hundred twenty-two".
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