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103031012013 = 334343670671
BaseRepresentation
bin101111111110100100…
…0000111101010101101
3100211221102000201001220
41133331020013222231
53142001414341023
6115155400053553
710305130103136
oct1377510075255
9324842021056
10103031012013
113a771358306
1217b74a642b9
13993c761787
144db581ac8d
152a303a73e3
hex17fd207aad

103031012013 has 4 divisors (see below), whose sum is σ = 137374682688. Its totient is φ = 68687341340.

The previous prime is 103031012003. The next prime is 103031012101. The reversal of 103031012013 is 310210130301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103031012013 - 26 = 103031011949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103031011983 and 103031012001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103031012003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17171835333 + ... + 17171835338.

It is an arithmetic number, because the mean of its divisors is an integer number (34343670672).

Almost surely, 2103031012013 is an apocalyptic number.

It is an amenable number.

103031012013 is a deficient number, since it is larger than the sum of its proper divisors (34343670675).

103031012013 is an equidigital number, since it uses as much as digits as its factorization.

103031012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34343670674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 103031012013 its reverse (310210130301), we get a palindrome (413241142314).

The spelling of 103031012013 in words is "one hundred three billion, thirty-one million, twelve thousand, thirteen".

Divisors: 1 3 34343670671 103031012013