103040142433 has 4 divisors (see below), whose sum is σ = 109101327300. Its totient is φ = 96978957568.

The previous prime is 103040142427. The next prime is 103040142449. The reversal of 103040142433 is 334241040301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 49767809569 + 53272332864 = 223087^2 + 230808^2 .

It is a cyclic number.

It is not a de Polignac number, because 103040142433 - 2²⁵ = 103006588001 is a prime.

It is a super-3 number, since 3×103040142433³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103040142398 and 103040142407.

It is not an unprimeable number, because it can be changed into a prime (103040142493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3030592408 + ... + 3030592441.

It is an arithmetic number, because the mean of its divisors is an integer number (27275331825).

Almost surely, 2^103040142433 is an apocalyptic number.

It is an amenable number.

103040142433 is a deficient number, since it is larger than the sum of its proper divisors (6061184867).

103040142433 is an equidigital number, since it uses as much as digits as its factorization.

103040142433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6061184866.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 103040142433 its reverse (334241040301), we get a palindrome (437281182734).

The spelling of 103040142433 in words is "one hundred three billion, forty million, one hundred forty-two thousand, four hundred thirty-three".