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103053615335 = 51115619119963
BaseRepresentation
bin101111111111001111…
…0010110000011100111
3100211222222120001222222
41133332132112003213
53142023211142320
6115201524342555
710305523164056
oct1377636260347
9324888501888
10103053615335
113a783096540
1217b80544a5b
139944346b18
144db882239d
152a3236e825
hex17fe7960e7

103053615335 has 16 divisors (see below), whose sum is σ = 134916312960. Its totient is φ = 74942660640.

The previous prime is 103053615317. The next prime is 103053615383. The reversal of 103053615335 is 533516350301.

It is not a de Polignac number, because 103053615335 - 28 = 103053615079 is a prime.

It is a super-2 number, since 2×1030536153352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103053615295 and 103053615304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 799064 + ... + 919026.

It is an arithmetic number, because the mean of its divisors is an integer number (8432269560).

Almost surely, 2103053615335 is an apocalyptic number.

103053615335 is a deficient number, since it is larger than the sum of its proper divisors (31862697625).

103053615335 is a wasteful number, since it uses less digits than its factorization.

103053615335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135598.

The product of its (nonzero) digits is 60750, while the sum is 35.

Adding to 103053615335 its reverse (533516350301), we get a palindrome (636569965636).

The spelling of 103053615335 in words is "one hundred three billion, fifty-three million, six hundred fifteen thousand, three hundred thirty-five".

Divisors: 1 5 11 55 15619 78095 119963 171809 599815 859045 1319593 6597965 1873702097 9368510485 20610723067 103053615335