Base | Representation |
---|---|
bin | 10111011100010011010111… |
… | …000011111111101101011101 |
3 | 111112001021010111002202120122 |
4 | 113130103113003333231131 |
5 | 102003142301244401023 |
6 | 1003135253152124325 |
7 | 30500505122000042 |
oct | 2734232703775535 |
9 | 445037114082518 |
10 | 103100003122013 |
11 | 2a93a513a50627 |
12 | b69157a5366a5 |
13 | 456b39a009611 |
14 | 1b660d133d1c9 |
15 | bdbd036682c8 |
hex | 5dc4d70ffb5d |
103100003122013 has 6 divisors (see below), whose sum is σ = 106533093757662. Its totient is φ = 99774196568760.
The previous prime is 103100003122007. The next prime is 103100003122033. The reversal of 103100003122013 is 310221300001301.
It can be written as a sum of positive squares in only one way, i.e., 81466834706404 + 21633168415609 = 9025898^2 + 4651147^2 .
It is a de Polignac number, because none of the positive numbers 2k-103100003122013 is a prime.
It is a super-2 number, since 2×1031000031220132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 103100003121982 and 103100003122000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103100003122033) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 53642040206 + ... + 53642042127.
It is an arithmetic number, because the mean of its divisors is an integer number (17755515626277).
Almost surely, 2103100003122013 is an apocalyptic number.
It is an amenable number.
103100003122013 is a deficient number, since it is larger than the sum of its proper divisors (3433090635649).
103100003122013 is an equidigital number, since it uses as much as digits as its factorization.
103100003122013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107284082395 (or 107284082364 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 103100003122013 its reverse (310221300001301), we get a palindrome (413321303123314).
The spelling of 103100003122013 in words is "one hundred three trillion, one hundred billion, three million, one hundred twenty-two thousand, thirteen".
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