10310112212999 has 4 divisors (see below), whose sum is σ = 10310280183336. Its totient is φ = 10309944242664.

The previous prime is 10310112212977. The next prime is 10310112213001. The reversal of 10310112212999 is 99921221101301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10310112212999 is a prime.

It is a super-4 number, since 4×10310112212999⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10310112212599) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83893064 + ... + 84015869.

It is an arithmetic number, because the mean of its divisors is an integer number (2577570045834).

Almost surely, 2^{10310112212999} is an apocalyptic number.

10310112212999 is a deficient number, since it is larger than the sum of its proper divisors (167970337).

10310112212999 is an equidigital number, since it uses as much as digits as its factorization.

10310112212999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167970336.

The product of its (nonzero) digits is 17496, while the sum is 41.

The spelling of 10310112212999 in words is "ten trillion, three hundred ten billion, one hundred twelve million, two hundred twelve thousand, nine hundred ninety-nine".