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10311312012314 = 25155656006157
BaseRepresentation
bin1001011000001100101000…
…0101101111010000011010
31100111202022001201001020112
42112003022011233100122
52322420031333343224
633532541253524322
72112652631652455
oct226031205572032
940452261631215
1010311312012314
1133160038a7625
1211a64996436a2
1359a477727031
142790da76049c
1512d34a77430e
hex960ca16f41a

10311312012314 has 4 divisors (see below), whose sum is σ = 15466968018474. Its totient is φ = 5155656006156.

The previous prime is 10311312012311. The next prime is 10311312012329. The reversal of 10311312012314 is 41321021311301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 5670661129225 + 4640650883089 = 2381315^2 + 2154217^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 10311312012314.

It is not an unprimeable number, because it can be changed into a prime (10311312012311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2577828003077 + ... + 2577828003080.

Almost surely, 210311312012314 is an apocalyptic number.

10311312012314 is a deficient number, since it is larger than the sum of its proper divisors (5155656006160).

10311312012314 is an equidigital number, since it uses as much as digits as its factorization.

10311312012314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5155656006159.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 10311312012314 its reverse (41321021311301), we get a palindrome (51632333323615).

The spelling of 10311312012314 in words is "ten trillion, three hundred eleven billion, three hundred twelve million, twelve thousand, three hundred fourteen".

Divisors: 1 2 5155656006157 10311312012314