Base | Representation |
---|---|
bin | 110000000001000001… |
… | …0000001110011101111 |
3 | 100212011010212102122201 |
4 | 1200002002001303233 |
5 | 3142134001114411 |
6 | 115211455522331 |
7 | 10310146412323 |
oct | 1400202016357 |
9 | 325133772581 |
10 | 103113301231 |
11 | 3a803852426 |
12 | 17b985293a7 |
13 | 9953813b15 |
14 | 4dc271b983 |
15 | 2a3770e3c1 |
hex | 1802081cef |
103113301231 has 4 divisors (see below), whose sum is σ = 103120368264. Its totient is φ = 103106234200.
The previous prime is 103113301217. The next prime is 103113301241. The reversal of 103113301231 is 132103311301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 103113301231 - 25 = 103113301199 is a prime.
It is a super-2 number, since 2×1031133012312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 103113301199 and 103113301208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103113301211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3511585 + ... + 3540826.
It is an arithmetic number, because the mean of its divisors is an integer number (25780092066).
Almost surely, 2103113301231 is an apocalyptic number.
103113301231 is a deficient number, since it is larger than the sum of its proper divisors (7067033).
103113301231 is an equidigital number, since it uses as much as digits as its factorization.
103113301231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7067032.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 103113301231 its reverse (132103311301), we get a palindrome (235216612532).
The spelling of 103113301231 in words is "one hundred three billion, one hundred thirteen million, three hundred one thousand, two hundred thirty-one".
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