10312000013 has 4 divisors (see below), whose sum is σ = 11785142880. Its totient is φ = 8838857148.

The previous prime is 10311999947. The next prime is 10312000033. The reversal of 10312000013 is 31000021301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31000021301 = 1723 ⋅17991887.

It is a cyclic number.

It is not a de Polignac number, because 10312000013 - 2¹⁰ = 10311998989 is a prime.

It is a super-2 number, since 2×10312000013² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10311999958 and 10312000003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10312000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736571423 + ... + 736571436.

It is an arithmetic number, because the mean of its divisors is an integer number (2946285720).

Almost surely, 2^10312000013 is an apocalyptic number.

It is an amenable number.

10312000013 is a deficient number, since it is larger than the sum of its proper divisors (1473142867).

10312000013 is an equidigital number, since it uses as much as digits as its factorization.

10312000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1473142866.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 10312000013 its reverse (31000021301), we get a palindrome (41312021314).

The spelling of 10312000013 in words is "ten billion, three hundred twelve million, thirteen", and thus it is an aban number.