1031201300113 has 4 divisors (see below), whose sum is σ = 1032199559908. Its totient is φ = 1030203040320.

The previous prime is 1031201300081. The next prime is 1031201300147. The reversal of 1031201300113 is 3110031021301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1015292018689 + 15909281424 = 1007617^2 + 126132^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031201300113 - 2⁵ = 1031201300081 is a prime.

It is a super-2 number, since 2×1031201300113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1031201303113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 499128348 + ... + 499130413.

It is an arithmetic number, because the mean of its divisors is an integer number (258049889977).

Almost surely, 2^{1031201300113} is an apocalyptic number.

It is an amenable number.

1031201300113 is a deficient number, since it is larger than the sum of its proper divisors (998259795).

1031201300113 is an equidigital number, since it uses as much as digits as its factorization.

1031201300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 998259794.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1031201300113 its reverse (3110031021301), we get a palindrome (4141232321414).

The spelling of 1031201300113 in words is "one trillion, thirty-one billion, two hundred one million, three hundred thousand, one hundred thirteen".