Base | Representation |
---|---|
bin | 11110000000110000110… |
… | …00110010101001001001 |
3 | 10122120201012011211221001 |
4 | 33000120120302221021 |
5 | 113343400013144423 |
6 | 2105421034415001 |
7 | 134334062311222 |
oct | 17003030625111 |
9 | 3576635154831 |
10 | 1031201303113 |
11 | 36836a285813 |
12 | 147a2b291461 |
13 | 7631b4c0287 |
14 | 37ca6240249 |
15 | 1bc55a86cad |
hex | f018632a49 |
1031201303113 has 2 divisors, whose sum is σ = 1031201303114. Its totient is φ = 1031201303112.
The previous prime is 1031201303059. The next prime is 1031201303149. The reversal of 1031201303113 is 3113031021301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 876447971344 + 154753331769 = 936188^2 + 393387^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031201303113 - 229 = 1030664432201 is a prime.
It is a super-2 number, since 2×10312013031132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1031201309113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515600651556 + 515600651557.
It is an arithmetic number, because the mean of its divisors is an integer number (515600651557).
Almost surely, 21031201303113 is an apocalyptic number.
It is an amenable number.
1031201303113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031201303113 is an equidigital number, since it uses as much as digits as its factorization.
1031201303113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1031201303113 its reverse (3113031021301), we get a palindrome (4144232324414).
The spelling of 1031201303113 in words is "one trillion, thirty-one billion, two hundred one million, three hundred three thousand, one hundred thirteen".
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