Base | Representation |
---|---|
bin | 110000000001001111… |
… | …1011100101001101011 |
3 | 100212011200101020200221 |
4 | 1200002133130221223 |
5 | 3142142434411410 |
6 | 115212333110511 |
7 | 10310302102543 |
oct | 1400237345153 |
9 | 325150336627 |
10 | 103121013355 |
11 | 3a80813a688 |
12 | 17b9b028437 |
13 | 99552b41c9 |
14 | 4dc3768323 |
15 | 2a382344da |
hex | 18027dca6b |
103121013355 has 12 divisors (see below), whose sum is σ = 127180080720. Its totient is φ = 80267161824.
The previous prime is 103121013349. The next prime is 103121013403. The reversal of 103121013355 is 553310121301.
It is not a de Polignac number, because 103121013355 - 25 = 103121013323 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7525735 + ... + 7539424.
It is an arithmetic number, because the mean of its divisors is an integer number (10598340060).
Almost surely, 2103121013355 is an apocalyptic number.
103121013355 is a deficient number, since it is larger than the sum of its proper divisors (24059067365).
103121013355 is an equidigital number, since it uses as much as digits as its factorization.
103121013355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15065238 (or 15065201 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 103121013355 its reverse (553310121301), we get a palindrome (656431134656).
The spelling of 103121013355 in words is "one hundred three billion, one hundred twenty-one million, thirteen thousand, three hundred fifty-five".
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