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10312102023 = 37943510979
BaseRepresentation
bin10011001101010011…
…00011000010000111
3222121200001001121120
421212221203002013
5132104344231043
64423132045023
7513354264246
oct114651430207
928550031546
1010312102023
114411a04973
121bb9603773
13c84564822
146db7a695d
154054ac983
hex266a63087

10312102023 has 8 divisors (see below), whose sum is σ = 13923513600. Its totient is φ = 6787712568.

The previous prime is 10312102013. The next prime is 10312102037. The reversal of 10312102023 is 32020121301.

10312102023 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10312102023 - 25 = 10312101991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10312101993 and 10312102011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10312102013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21755253 + ... + 21755726.

It is an arithmetic number, because the mean of its divisors is an integer number (1740439200).

Almost surely, 210312102023 is an apocalyptic number.

10312102023 is a deficient number, since it is larger than the sum of its proper divisors (3611411577).

10312102023 is an equidigital number, since it uses as much as digits as its factorization.

10312102023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43511061.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10312102023 its reverse (32020121301), we get a palindrome (42332223324).

The spelling of 10312102023 in words is "ten billion, three hundred twelve million, one hundred two thousand, twenty-three".

Divisors: 1 3 79 237 43510979 130532937 3437367341 10312102023