103121131300000 has 1152 divisors, whose sum is σ = 300572977098240. Its totient is φ = 34406400000000.

The previous prime is 103121131299943. The next prime is 103121131300009. The reversal of 103121131300000 is 3131121301.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (103121131300009) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 134097699616 + ... + 134097700384.

It is an arithmetic number, because the mean of its divisors is an integer number (260914042620).

Almost surely, 2^{103121131300000} is an apocalyptic number.

103121131300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103121131300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150286488549120).

103121131300000 is an abundant number, since it is smaller than the sum of its proper divisors (197451845798240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103121131300000 is a wasteful number, since it uses less digits than its factorization.

103121131300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1004 (or 976 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103121131300000 its reverse (3131121301), we get a palindrome (103124262421301).

The spelling of 103121131300000 in words is "one hundred three trillion, one hundred twenty-one billion, one hundred thirty-one million, three hundred thousand".