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10312121341 = 17606595373
BaseRepresentation
bin10011001101010011…
…00111101111111101
3222121200002001010001
421212221213233331
5132104400340331
64423132314301
7513354404464
oct114651475775
928550061101
1010312121341
114411a18435
121bb9612991
13c84570562
146db7ad9db
154054b3561
hex266a67bfd

10312121341 has 4 divisors (see below), whose sum is σ = 10918716732. Its totient is φ = 9705525952.

The previous prime is 10312121333. The next prime is 10312121359. The reversal of 10312121341 is 14312121301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14312121301 = 107133758143.

It can be written as a sum of positive squares in 2 ways, for example, as 6950556900 + 3361564441 = 83370^2 + 57979^2 .

It is a cyclic number.

It is not a de Polignac number, because 10312121341 - 23 = 10312121333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10312101341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 303297670 + ... + 303297703.

It is an arithmetic number, because the mean of its divisors is an integer number (2729679183).

Almost surely, 210312121341 is an apocalyptic number.

It is an amenable number.

10312121341 is a deficient number, since it is larger than the sum of its proper divisors (606595391).

10312121341 is an equidigital number, since it uses as much as digits as its factorization.

10312121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 606595390.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10312121341 its reverse (14312121301), we get a palindrome (24624242642).

The spelling of 10312121341 in words is "ten billion, three hundred twelve million, one hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 17 606595373 10312121341