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103125320503053 = 3172022065107903
BaseRepresentation
bin10111011100101010111100…
…000110001000111100001101
3111112010200110220012222022220
4113130222330012020330031
5102004101124022044203
61003155041311325553
730502362402121422
oct2734527406107415
9445120426188286
10103125320503053
112a94a225a52732
12b6964652208b9
1345708a3217c64
141b67413901d49
15bdc7d612e653
hex5dcabc188f0d

103125320503053 has 8 divisors (see below), whose sum is σ = 145588687769088. Its totient is φ = 64706083452864.

The previous prime is 103125320503031. The next prime is 103125320503057. The reversal of 103125320503053 is 350305023521301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 103125320503053 - 212 = 103125320498957 is a prime.

It is a super-3 number, since 3×1031253205030533 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103125320503057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1011032553901 + ... + 1011032554002.

It is an arithmetic number, because the mean of its divisors is an integer number (18198585971136).

Almost surely, 2103125320503053 is an apocalyptic number.

It is an amenable number.

103125320503053 is a deficient number, since it is larger than the sum of its proper divisors (42463367266035).

103125320503053 is a wasteful number, since it uses less digits than its factorization.

103125320503053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2022065107923.

The product of its (nonzero) digits is 40500, while the sum is 33.

The spelling of 103125320503053 in words is "one hundred three trillion, one hundred twenty-five billion, three hundred twenty million, five hundred three thousand, fifty-three".

Divisors: 1 3 17 51 2022065107903 6066195323709 34375106834351 103125320503053