10313000622241 has 4 divisors (see below), whose sum is σ = 10315516606000. Its totient is φ = 10310484638484.

The previous prime is 10313000622203. The next prime is 10313000622251. The reversal of 10313000622241 is 14222600031301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10313000622241 - 2¹¹ = 10313000620193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10313000622251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1257985731 + ... + 1257993928.

It is an arithmetic number, because the mean of its divisors is an integer number (2578879151500).

Almost surely, 2^{10313000622241} is an apocalyptic number.

It is an amenable number.

10313000622241 is a deficient number, since it is larger than the sum of its proper divisors (2515983759).

10313000622241 is an equidigital number, since it uses as much as digits as its factorization.

10313000622241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2515983758.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10313000622241 its reverse (14222600031301), we get a palindrome (24535600653542).

The spelling of 10313000622241 in words is "ten trillion, three hundred thirteen billion, six hundred twenty-two thousand, two hundred forty-one".