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1031300100143 = 1121391973611
BaseRepresentation
bin11110000000111100100…
…01101011000000101111
310122120222002002020222022
433000132101223000233
5113344100311201033
62105434524140355
7134336402133215
oct17003621530057
93576862066868
101031300100143
11368410025455
12147a583976bb
1376335b02361
1437cb53dacb5
151bc5e5a0098
hexf01e46b02f

1031300100143 has 4 divisors (see below), whose sum is σ = 1031392084968. Its totient is φ = 1031208115320.

The previous prime is 1031300100119. The next prime is 1031300100161. The reversal of 1031300100143 is 3410010031301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1031300100143 - 220 = 1031299051567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031300108143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45975593 + ... + 45998018.

It is an arithmetic number, because the mean of its divisors is an integer number (257848021242).

Almost surely, 21031300100143 is an apocalyptic number.

1031300100143 is a deficient number, since it is larger than the sum of its proper divisors (91984825).

1031300100143 is an equidigital number, since it uses as much as digits as its factorization.

1031300100143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91984824.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1031300100143 its reverse (3410010031301), we get a palindrome (4441310131444).

The spelling of 1031300100143 in words is "one trillion, thirty-one billion, three hundred million, one hundred thousand, one hundred forty-three".

Divisors: 1 11213 91973611 1031300100143