10313004012 has 48 divisors (see below), whose sum is σ = 25089576960. Its totient is φ = 3292978752.

The previous prime is 10313004007. The next prime is 10313004047. The reversal of 10313004012 is 21040031301.

It is a super-2 number, since 2×10313004012² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10313003982 and 10313004000.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72478 + ... + 160869.

It is an arithmetic number, because the mean of its divisors is an integer number (522699520).

Almost surely, 2^10313004012 is an apocalyptic number.

10313004012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10313004012 is an abundant number, since it is smaller than the sum of its proper divisors (14776572948).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10313004012 is a wasteful number, since it uses less digits than its factorization.

10313004012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233510 (or 233508 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10313004012 its reverse (21040031301), we get a palindrome (31353035313).

The spelling of 10313004012 in words is "ten billion, three hundred thirteen million, four thousand, twelve".