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10313011131300 = 223252791237117259
BaseRepresentation
bin1001011000010010111101…
…0111010111001110100100
31100111220200110220020022100
42112010233113113032210
52322432021322200200
633533422031532100
72113043013145233
oct226045727271644
940456613806270
1010313011131300
1133167a5a18899
1211a689268a030
1359a688755597
1427921c296b1a
1512d3e9a01d00
hex9612f5d73a4

10313011131300 has 216 divisors, whose sum is σ = 32761487158400. Its totient is φ = 2713106223360.

The previous prime is 10313011131287. The next prime is 10313011131323. The reversal of 10313011131300 is 313111031301.

10313011131300 is a `hidden beast` number, since 1 + 0 + 31 + 301 + 1 + 1 + 31 + 300 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 87892071 + ... + 88009329.

Almost surely, 210313011131300 is an apocalyptic number.

10313011131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10313011131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16380743579200).

10313011131300 is an abundant number, since it is smaller than the sum of its proper divisors (22448476027100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10313011131300 is a wasteful number, since it uses less digits than its factorization.

10313011131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118595 (or 118585 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 10313011131300 its reverse (313111031301), we get a palindrome (10626122162601).

Subtracting from 10313011131300 its reverse (313111031301), we obtain a palindrome (9999900099999).

The spelling of 10313011131300 in words is "ten trillion, three hundred thirteen billion, eleven million, one hundred thirty-one thousand, three hundred".