1031313233113 has 4 divisors (see below), whose sum is σ = 1048793118480. Its totient is φ = 1013833347748.

The previous prime is 1031313233107. The next prime is 1031313233129. The reversal of 1031313233113 is 3113323131301.

1031313233113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1031313233113 - 2⁵ = 1031313233081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1031313233173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8739942595 + ... + 8739942712.

It is an arithmetic number, because the mean of its divisors is an integer number (262198279620).

Almost surely, 2^{1031313233113} is an apocalyptic number.

It is an amenable number.

1031313233113 is a deficient number, since it is larger than the sum of its proper divisors (17479885367).

1031313233113 is an equidigital number, since it uses as much as digits as its factorization.

1031313233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17479885366.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1031313233113 its reverse (3113323131301), we get a palindrome (4144636364414).

The spelling of 1031313233113 in words is "one trillion, thirty-one billion, three hundred thirteen million, two hundred thirty-three thousand, one hundred thirteen".