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10313142440343 = 33437714146781
BaseRepresentation
bin1001011000010011011100…
…1100010001000110010111
31100111221000121222102110020
42112010313030101012113
52322432303431042333
633533443042200223
72113046166230361
oct226046714210627
940457017872406
1010313142440343
113316863054266
1211a690a653073
1359a6a9a0bb42
142792318b7d31
1512d4062dd3b3
hex96137311197

10313142440343 has 4 divisors (see below), whose sum is σ = 13750856587128. Its totient is φ = 6875428293560.

The previous prime is 10313142440323. The next prime is 10313142440357. The reversal of 10313142440343 is 34304424131301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10313142440343 - 238 = 10038264533399 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10313142440323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1718857073388 + ... + 1718857073393.

It is an arithmetic number, because the mean of its divisors is an integer number (3437714146782).

Almost surely, 210313142440343 is an apocalyptic number.

10313142440343 is a deficient number, since it is larger than the sum of its proper divisors (3437714146785).

10313142440343 is an equidigital number, since it uses as much as digits as its factorization.

10313142440343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3437714146784.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 10313142440343 its reverse (34304424131301), we get a palindrome (44617566571644).

The spelling of 10313142440343 in words is "ten trillion, three hundred thirteen billion, one hundred forty-two million, four hundred forty thousand, three hundred forty-three".

Divisors: 1 3 3437714146781 10313142440343