103132113101 has 4 divisors (see below), whose sum is σ = 103133010432. Its totient is φ = 103131215772.

The previous prime is 103132113089. The next prime is 103132113121. The reversal of 103132113101 is 101311231301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 103132113101 - 2²² = 103127918797 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 103132113101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103132113121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245645 + ... + 516338.

It is an arithmetic number, because the mean of its divisors is an integer number (25783252608).

Almost surely, 2^103132113101 is an apocalyptic number.

It is an amenable number.

103132113101 is a deficient number, since it is larger than the sum of its proper divisors (897331).

103132113101 is an equidigital number, since it uses as much as digits as its factorization.

103132113101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 897330.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 103132113101 its reverse (101311231301), we get a palindrome (204443344402).

The spelling of 103132113101 in words is "one hundred three billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred one".