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10313321120122 = 25156660560061
BaseRepresentation
bin1001011000010100000111…
…0101111000000101111010
31100111221111002012022000211
42112011001311320011322
52322433140201320442
633533512504021334
72113053466046566
oct226050165700572
940457432168024
1010313321120122
1133169449a4aa9
1211a695a46184a
1359a707a3cb17
1427924b50a6a6
1512d416d35617
hex96141d7817a

10313321120122 has 4 divisors (see below), whose sum is σ = 15469981680186. Its totient is φ = 5156660560060.

The previous prime is 10313321120071. The next prime is 10313321120189. The reversal of 10313321120122 is 22102112331301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10165696880161 + 147624239961 = 3188369^2 + 384219^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10313321120093 and 10313321120102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2578330280029 + ... + 2578330280032.

Almost surely, 210313321120122 is an apocalyptic number.

10313321120122 is a deficient number, since it is larger than the sum of its proper divisors (5156660560064).

10313321120122 is an equidigital number, since it uses as much as digits as its factorization.

10313321120122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5156660560063.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10313321120122 its reverse (22102112331301), we get a palindrome (32415433451423).

The spelling of 10313321120122 in words is "ten trillion, three hundred thirteen billion, three hundred twenty-one million, one hundred twenty thousand, one hundred twenty-two".

Divisors: 1 2 5156660560061 10313321120122