Base | Representation |
---|---|
bin | 1001011000010100001001… |
… | …1000100001001001110011 |
3 | 1100111221111201021122221011 |
4 | 2112011002120201021303 |
5 | 2322433200012414303 |
6 | 33533513430411351 |
7 | 2113053636201211 |
oct | 226050230411163 |
9 | 40457451248834 |
10 | 10313330201203 |
11 | 331694a037827 |
12 | 11a6961500b57 |
13 | 59a70989c343 |
14 | 27924c7d1cb1 |
15 | 12d417a2b16d |
hex | 96142621273 |
10313330201203 has 4 divisors (see below), whose sum is σ = 10313428855608. Its totient is φ = 10313231546800.
The previous prime is 10313330201197. The next prime is 10313330201227. The reversal of 10313330201203 is 30210203331301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10313330201203 - 229 = 10312793330291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10313330201263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49170226 + ... + 49379527.
It is an arithmetic number, because the mean of its divisors is an integer number (2578357213902).
Almost surely, 210313330201203 is an apocalyptic number.
10313330201203 is a deficient number, since it is larger than the sum of its proper divisors (98654405).
10313330201203 is an equidigital number, since it uses as much as digits as its factorization.
10313330201203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98654404.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 10313330201203 its reverse (30210203331301), we get a palindrome (40523533532504).
The spelling of 10313330201203 in words is "ten trillion, three hundred thirteen billion, three hundred thirty million, two hundred one thousand, two hundred three".
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