Base | Representation |
---|---|
bin | 10111011100110011001101… |
… | …100000000000011101000101 |
3 | 111112011112101220010200100101 |
4 | 113130303031200000131011 |
5 | 102004222321310300201 |
6 | 1003203110514044101 |
7 | 30503125452222106 |
oct | 2734631540003505 |
9 | 445145356120311 |
10 | 103134202431301 |
11 | 2a952a736298a8 |
12 | b698123879631 |
13 | 457168a397bc2 |
14 | 1b67a173803ad |
15 | bdcb55c86d01 |
hex | 5dcccd800745 |
103134202431301 has 4 divisors (see below), whose sum is σ = 103134302537292. Its totient is φ = 103134102325312.
The previous prime is 103134202431287. The next prime is 103134202431317.
103134202431301 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 67076591400900 + 36057611030401 = 8190030^2 + 6004799^2 .
It is a cyclic number.
It is not a de Polignac number, because 103134202431301 - 221 = 103134200334149 is a prime.
It is a super-2 number, since 2×1031342024313012 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 103134202431301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103134202431361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48491380 + ... + 50573533.
It is an arithmetic number, because the mean of its divisors is an integer number (25783575634323).
Almost surely, 2103134202431301 is an apocalyptic number.
It is an amenable number.
103134202431301 is a deficient number, since it is larger than the sum of its proper divisors (100105991).
103134202431301 is an equidigital number, since it uses as much as digits as its factorization.
103134202431301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100105990.
The product of its (nonzero) digits is 5184, while the sum is 28.
It can be divided in two parts, 10313420 and 2431301, that added together give a palindrome (12744721).
The spelling of 103134202431301 in words is "one hundred three trillion, one hundred thirty-four billion, two hundred two million, four hundred thirty-one thousand, three hundred one".
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