10314011213 has 4 divisors (see below), whose sum is σ = 11251648608. Its totient is φ = 9376373820.

The previous prime is 10314011203. The next prime is 10314011251. The reversal of 10314011213 is 31211041301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-10314011213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10314011191 and 10314011200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10314011203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468818681 + ... + 468818702.

It is an arithmetic number, because the mean of its divisors is an integer number (2812912152).

Almost surely, 2^10314011213 is an apocalyptic number.

It is an amenable number.

10314011213 is a deficient number, since it is larger than the sum of its proper divisors (937637395).

10314011213 is an equidigital number, since it uses as much as digits as its factorization.

10314011213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 937637394.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10314011213 its reverse (31211041301), we get a palindrome (41525052514).

The spelling of 10314011213 in words is "ten billion, three hundred fourteen million, eleven thousand, two hundred thirteen".