Base | Representation |
---|---|
bin | 1001011000010110101110… |
… | …0001000011000010111011 |
3 | 1100112000021210211110200021 |
4 | 2112011223201003002323 |
5 | 2322441103144144120 |
6 | 33534110121551311 |
7 | 2113110016026001 |
oct | 226055341030273 |
9 | 40460253743607 |
10 | 10314020303035 |
11 | 3317173636519 |
12 | 11a6b14645537 |
13 | 59a7b9854317 |
14 | 2792b6310a71 |
15 | 12d4583e5aaa |
hex | 9616b8430bb |
10314020303035 has 4 divisors (see below), whose sum is σ = 12376824363648. Its totient is φ = 8251216242424.
The previous prime is 10314020303029. The next prime is 10314020303047. The reversal of 10314020303035 is 53030302041301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10314020303035 - 25 = 10314020303003 is a prime.
It is a super-2 number, since 2×103140203030352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031402030299 + ... + 1031402030308.
It is an arithmetic number, because the mean of its divisors is an integer number (3094206090912).
Almost surely, 210314020303035 is an apocalyptic number.
10314020303035 is a deficient number, since it is larger than the sum of its proper divisors (2062804060613).
10314020303035 is an equidigital number, since it uses as much as digits as its factorization.
10314020303035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2062804060612.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 10314020303035 its reverse (53030302041301), we get a palindrome (63344322344336).
The spelling of 10314020303035 in words is "ten trillion, three hundred fourteen billion, twenty million, three hundred three thousand, thirty-five".
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