103141114310131 has 4 divisors (see below), whose sum is σ = 103321746735064. Its totient is φ = 102960481885200.

The previous prime is 103141114310099. The next prime is 103141114310159. The reversal of 103141114310131 is 131013411141301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103141114310131 - 2⁵ = 103141114310099 is a prime.

It is a super-2 number, since 2×103141114310131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103141114310096 and 103141114310105.

It is not an unprimeable number, because it can be changed into a prime (103141114320131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90316211610 + ... + 90316212751.

It is an arithmetic number, because the mean of its divisors is an integer number (25830436683766).

Almost surely, 2^{103141114310131} is an apocalyptic number.

103141114310131 is a deficient number, since it is larger than the sum of its proper divisors (180632424933).

103141114310131 is an equidigital number, since it uses as much as digits as its factorization.

103141114310131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180632424932.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 103141114310131 its reverse (131013411141301), we get a palindrome (234154525451432).

The spelling of 103141114310131 in words is "one hundred three trillion, one hundred forty-one billion, one hundred fourteen million, three hundred ten thousand, one hundred thirty-one".