Base | Representation |
---|---|
bin | 1001011000010111011100… |
… | …0000100011100111110001 |
3 | 1100112000210020122012021100 |
4 | 2112011313000203213301 |
5 | 2322442002024043210 |
6 | 33534141210315013 |
7 | 2113114546624104 |
oct | 226056700434761 |
9 | 40460706565240 |
10 | 10314213112305 |
11 | 3317262457a23 |
12 | 11a6b69128a69 |
13 | 59a81a79164b |
14 | 2792d3b8073b |
15 | 12d46a2ce5c0 |
hex | 961770239f1 |
10314213112305 has 72 divisors (see below), whose sum is σ = 18573073713792. Its totient is φ = 5292617082048.
The previous prime is 10314213112163. The next prime is 10314213112327. The reversal of 10314213112305 is 50321131241301.
10314213112305 is a `hidden beast` number, since 1 + 0 + 3 + 1 + 42 + 1 + 311 + 2 + 305 = 666.
It is not a de Polignac number, because 10314213112305 - 222 = 10314208918001 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 6661842 + ... + 8062788.
It is an arithmetic number, because the mean of its divisors is an integer number (257959357136).
Almost surely, 210314213112305 is an apocalyptic number.
10314213112305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10314213112305 is a deficient number, since it is larger than the sum of its proper divisors (8258860601487).
10314213112305 is a wasteful number, since it uses less digits than its factorization.
10314213112305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1401123 (or 1401061 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 10314213112305 its reverse (50321131241301), we get a palindrome (60635344353606).
The spelling of 10314213112305 in words is "ten trillion, three hundred fourteen billion, two hundred thirteen million, one hundred twelve thousand, three hundred five".
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